x^4-1/4x^2-3/8=0

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Solution for x^4-1/4x^2-3/8=0 equation: 


x in (-oo:+oo)

x^4-((1/4)*x^2)-(3/8) = 0

x^4+(-1/4)*x^2-3/8 = 0

x^4-1/4*x^2-3/8 = 0

t_1 = x^2

1*t_1^2-1/4*t_1^1-3/8 = 0

t_1^2-1/4*t_1-3/8 = 0

DELTA = (-1/4)^2-(-3/8*1*4)

DELTA = 25/16

DELTA > 0

t_1 = ((25/16)^(1/2)+1/4)/(1*2) or t_1 = (1/4-(25/16)^(1/2))/(1*2)

t_1 = 3/4 or t_1 = -1/2

t_1 = -1/2

x^2+1/2 = 0

1*x^2 = -1/2 // : 1

x^2 = -1/2

t_1 = 3/4

x^2-3/4 = 0

1*x^2 = 3/4 // : 1

x^2 = 3/4

x^2 = 3/4 // ^ 1/2

abs(x) = (3/4)^(1/2)

x = (3/4)^(1/2) or x = -(3/4)^(1/2)

x in { (3/4)^(1/2), -(3/4)^(1/2) }

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